(x+4)^2-2x-5=x^2+1

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Solution for (x+4)^2-2x-5=x^2+1 equation: 



(x+4)^2-2x-5=x^2+1

We move all terms to the left:

(x+4)^2-2x-5-(x^2+1)=0

We add all the numbers together, and all the variables

-2x+(x+4)^2-(x^2+1)-5=0

We get rid of parentheses

-x^2-2x+(x+4)^2-1-5=0

We add all the numbers together, and all the variables

-1x^2-2x+(x+4)^2-6=0

We move all terms containing x to the left, all other terms to the right

-1x^2-2x+(x+4)^2=6

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